Base | Representation |
---|---|
bin | 1011111101101011011010… |
… | …0001101000101110110001 |
3 | 1201120112102110002200122121 |
4 | 2333122312201220232301 |
5 | 3211004402021144444 |
6 | 43550551403034241 |
7 | 2525235426155635 |
oct | 277326641505661 |
9 | 51515373080577 |
10 | 13154252131249 |
11 | 4211761440aa9 |
12 | 158547050b981 |
13 | 745596166a68 |
14 | 3369523dcdc5 |
15 | 17c28b6e2084 |
hex | bf6b6868bb1 |
13154252131249 has 2 divisors, whose sum is σ = 13154252131250. Its totient is φ = 13154252131248.
The previous prime is 13154252131243. The next prime is 13154252131283. The reversal of 13154252131249 is 94213125245131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13138138367649 + 16113763600 = 3624657^2 + 126940^2 .
It is an emirp because it is prime and its reverse (94213125245131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13154252131249 - 211 = 13154252129201 is a prime.
It is not a weakly prime, because it can be changed into another prime (13154252131243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6577126065624 + 6577126065625.
It is an arithmetic number, because the mean of its divisors is an integer number (6577126065625).
Almost surely, 213154252131249 is an apocalyptic number.
It is an amenable number.
13154252131249 is a deficient number, since it is larger than the sum of its proper divisors (1).
13154252131249 is an equidigital number, since it uses as much as digits as its factorization.
13154252131249 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 259200, while the sum is 43.
The spelling of 13154252131249 in words is "thirteen trillion, one hundred fifty-four billion, two hundred fifty-two million, one hundred thirty-one thousand, two hundred forty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •