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13154322501361 is a prime number
BaseRepresentation
bin1011111101101011101010…
…1110000100111011110001
31201120112121100111212022001
42333122322232010323301
53211010023030020421
643551002355214001
72525240242253416
oct277327256047361
951515540455261
1013154322501361
114211798135118
12158548bba7301
137455a7904b92
1433695b8ba10d
1517c292992691
hexbf6bab84ef1

13154322501361 has 2 divisors, whose sum is σ = 13154322501362. Its totient is φ = 13154322501360.

The previous prime is 13154322501347. The next prime is 13154322501391. The reversal of 13154322501361 is 16310522345131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13152118762225 + 2203739136 = 3626585^2 + 46944^2 .

It is a cyclic number.

It is not a de Polignac number, because 13154322501361 - 211 = 13154322499313 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13154322501361.

It is not a weakly prime, because it can be changed into another prime (13154322501391) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6577161250680 + 6577161250681.

It is an arithmetic number, because the mean of its divisors is an integer number (6577161250681).

Almost surely, 213154322501361 is an apocalyptic number.

It is an amenable number.

13154322501361 is a deficient number, since it is larger than the sum of its proper divisors (1).

13154322501361 is an equidigital number, since it uses as much as digits as its factorization.

13154322501361 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64800, while the sum is 37.

Adding to 13154322501361 its reverse (16310522345131), we get a palindrome (29464844846492).

The spelling of 13154322501361 in words is "thirteen trillion, one hundred fifty-four billion, three hundred twenty-two million, five hundred one thousand, three hundred sixty-one".