Base | Representation |
---|---|
bin | 1011111101101011101011… |
… | …1000111100111001101100 |
3 | 1201120112121112212200200220 |
4 | 2333122322320330321230 |
5 | 3211010024242231134 |
6 | 43551002540251340 |
7 | 2525240305425432 |
oct | 277327270747154 |
9 | 51515545780626 |
10 | 13154325352044 |
11 | 4211799801958 |
12 | 1585490b40b50 |
13 | 7455a8392586 |
14 | 33695c01cd52 |
15 | 17c292d57149 |
hex | bf6bae3ce6c |
13154325352044 has 24 divisors (see below), whose sum is σ = 31522977871728. Its totient is φ = 4266267681600.
The previous prime is 13154325352043. The next prime is 13154325352067. The reversal of 13154325352044 is 44025352345131.
It is a junction number, because it is equal to n+sod(n) for n = 13154325351987 and 13154325352005.
It is not an unprimeable number, because it can be changed into a prime (13154325352043) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14813429007 + ... + 14813429894.
It is an arithmetic number, because the mean of its divisors is an integer number (1313457411322).
Almost surely, 213154325352044 is an apocalyptic number.
It is an amenable number.
13154325352044 is an abundant number, since it is smaller than the sum of its proper divisors (18368652519684).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13154325352044 is a wasteful number, since it uses less digits than its factorization.
13154325352044 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 29626858945 (or 29626858943 counting only the distinct ones).
The product of its (nonzero) digits is 864000, while the sum is 42.
Adding to 13154325352044 its reverse (44025352345131), we get a palindrome (57179677697175).
The spelling of 13154325352044 in words is "thirteen trillion, one hundred fifty-four billion, three hundred twenty-five million, three hundred fifty-two thousand, forty-four".
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