13154400254011 has 8 divisors (see below), whose sum is σ = 13924465386480. Its totient is φ = 12405432796512.

The previous prime is 13154400253999. The next prime is 13154400254033. The reversal of 13154400254011 is 11045200445131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13154400254011 - 2⁹ = 13154400253499 is a prime.

It is a super-2 number, since 2×13154400254011² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13154400254071) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5274417460 + ... + 5274419953.

It is an arithmetic number, because the mean of its divisors is an integer number (1740558173310).

Almost surely, 2^{13154400254011} is an apocalyptic number.

13154400254011 is a deficient number, since it is larger than the sum of its proper divisors (770065132469).

13154400254011 is a wasteful number, since it uses less digits than its factorization.

13154400254011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10548837485.

The product of its (nonzero) digits is 9600, while the sum is 31.

Adding to 13154400254011 its reverse (11045200445131), we get a palindrome (24199600699142).

The spelling of 13154400254011 in words is "thirteen trillion, one hundred fifty-four billion, four hundred million, two hundred fifty-four thousand, eleven".