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13154631595241 is a prime number
BaseRepresentation
bin1011111101101100110100…
…1001001011010011101001
31201120120101220010110101112
42333123031021023103221
53211011141142021431
643551053200200105
72525251014436643
oct277331511132351
951516356113345
1013154631595241
11421193665aa04
121585557609035
13745626967c76
1433698a979893
1517c2aeb9ac2b
hexbf6cd24b4e9

13154631595241 has 2 divisors, whose sum is σ = 13154631595242. Its totient is φ = 13154631595240.

The previous prime is 13154631595219. The next prime is 13154631595249. The reversal of 13154631595241 is 14259513645131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11439851821225 + 1714779774016 = 3382285^2 + 1309496^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13154631595241 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13154631595241.

It is not a weakly prime, because it can be changed into another prime (13154631595249) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6577315797620 + 6577315797621.

It is an arithmetic number, because the mean of its divisors is an integer number (6577315797621).

Almost surely, 213154631595241 is an apocalyptic number.

It is an amenable number.

13154631595241 is a deficient number, since it is larger than the sum of its proper divisors (1).

13154631595241 is an equidigital number, since it uses as much as digits as its factorization.

13154631595241 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1944000, while the sum is 50.

The spelling of 13154631595241 in words is "thirteen trillion, one hundred fifty-four billion, six hundred thirty-one million, five hundred ninety-five thousand, two hundred forty-one".