Base | Representation |
---|---|
bin | 11000100000001101… |
… | …00101000111011001 |
3 | 1020221210120101212011 |
4 | 30100012211013121 |
5 | 203420143442413 |
6 | 10013210345521 |
7 | 643665120055 |
oct | 142006450731 |
9 | 36853511764 |
10 | 13155062233 |
11 | 5640764a65 |
12 | 267172b2a1 |
13 | 1318553ac1 |
14 | 8cb1b0c65 |
15 | 51ed8133d |
hex | 3101a51d9 |
13155062233 has 2 divisors, whose sum is σ = 13155062234. Its totient is φ = 13155062232.
The previous prime is 13155062201. The next prime is 13155062237. The reversal of 13155062233 is 33226055131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10926939024 + 2228123209 = 104532^2 + 47203^2 .
It is a cyclic number.
It is not a de Polignac number, because 13155062233 - 25 = 13155062201 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13155062195 and 13155062204.
It is not a weakly prime, because it can be changed into another prime (13155062237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6577531116 + 6577531117.
It is an arithmetic number, because the mean of its divisors is an integer number (6577531117).
Almost surely, 213155062233 is an apocalyptic number.
It is an amenable number.
13155062233 is a deficient number, since it is larger than the sum of its proper divisors (1).
13155062233 is an equidigital number, since it uses as much as digits as its factorization.
13155062233 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16200, while the sum is 31.
The spelling of 13155062233 in words is "thirteen billion, one hundred fifty-five million, sixty-two thousand, two hundred thirty-three".
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