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131551541153353 is a prime number
BaseRepresentation
bin11101111010010100111010…
…111000010100111001001001
3122020210012112002102022002001
4131322110322320110321021
5114220320024013401403
61143441535501311001
736465166553001316
oct3572247270247111
9566705462368061
10131551541153353
1138a09771491a22
12129076a0b65461
135853345b0c269
14246b1b2ad1d0d
151031e56760c1d
hex77a53ae14e49

131551541153353 has 2 divisors, whose sum is σ = 131551541153354. Its totient is φ = 131551541153352.

The previous prime is 131551541153239. The next prime is 131551541153381. The reversal of 131551541153353 is 353351145155131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 89729620295184 + 41821920858169 = 9472572^2 + 6466987^2 .

It is an emirp because it is prime and its reverse (353351145155131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131551541153353 - 217 = 131551541022281 is a prime.

It is not a weakly prime, because it can be changed into another prime (131551541153453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65775770576676 + 65775770576677.

It is an arithmetic number, because the mean of its divisors is an integer number (65775770576677).

Almost surely, 2131551541153353 is an apocalyptic number.

It is an amenable number.

131551541153353 is a deficient number, since it is larger than the sum of its proper divisors (1).

131551541153353 is an equidigital number, since it uses as much as digits as its factorization.

131551541153353 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1012500, while the sum is 46.

The spelling of 131551541153353 in words is "one hundred thirty-one trillion, five hundred fifty-one billion, five hundred forty-one million, one hundred fifty-three thousand, three hundred fifty-three".