13155316424113 has 4 divisors (see below), whose sum is σ = 13156181977600. Its totient is φ = 13154450870628.

The previous prime is 13155316424027. The next prime is 13155316424119. The reversal of 13155316424113 is 31142461355131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13155316424113 - 2³³ = 13146726489521 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13155316424119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 432753945 + ... + 432784342.

It is an arithmetic number, because the mean of its divisors is an integer number (3289045494400).

Almost surely, 2^{13155316424113} is an apocalyptic number.

It is an amenable number.

13155316424113 is a deficient number, since it is larger than the sum of its proper divisors (865553487).

13155316424113 is an equidigital number, since it uses as much as digits as its factorization.

13155316424113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 865553486.

The product of its digits is 129600, while the sum is 40.

Adding to 13155316424113 its reverse (31142461355131), we get a palindrome (44297777779244).

The spelling of 13155316424113 in words is "thirteen trillion, one hundred fifty-five billion, three hundred sixteen million, four hundred twenty-four thousand, one hundred thirteen".