Base | Representation |
---|---|
bin | 1011111101101111110011… |
… | …0010110010110111011011 |
3 | 1201120122110121102011122201 |
4 | 2333123330302302313123 |
5 | 3211014310321044311 |
6 | 43551304355031031 |
7 | 2525306562526105 |
oct | 277337462626733 |
9 | 51518417364581 |
10 | 13155431034331 |
11 | 4212206948373 |
12 | 158573b29b477 |
13 | 745723482751 |
14 | 336a24bda575 |
15 | 17c309e619c1 |
hex | bf6fccb2ddb |
13155431034331 has 2 divisors, whose sum is σ = 13155431034332. Its totient is φ = 13155431034330.
The previous prime is 13155431034293. The next prime is 13155431034353. The reversal of 13155431034331 is 13343013455131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13155431034331 - 211 = 13155431032283 is a prime.
It is a super-2 number, since 2×131554310343312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13155431038331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6577715517165 + 6577715517166.
It is an arithmetic number, because the mean of its divisors is an integer number (6577715517166).
Almost surely, 213155431034331 is an apocalyptic number.
13155431034331 is a deficient number, since it is larger than the sum of its proper divisors (1).
13155431034331 is an equidigital number, since it uses as much as digits as its factorization.
13155431034331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 97200, while the sum is 37.
Adding to 13155431034331 its reverse (13343013455131), we get a palindrome (26498444489462).
The spelling of 13155431034331 in words is "thirteen trillion, one hundred fifty-five billion, four hundred thirty-one million, thirty-four thousand, three hundred thirty-one".
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