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13155431034331 is a prime number
BaseRepresentation
bin1011111101101111110011…
…0010110010110111011011
31201120122110121102011122201
42333123330302302313123
53211014310321044311
643551304355031031
72525306562526105
oct277337462626733
951518417364581
1013155431034331
114212206948373
12158573b29b477
13745723482751
14336a24bda575
1517c309e619c1
hexbf6fccb2ddb

13155431034331 has 2 divisors, whose sum is σ = 13155431034332. Its totient is φ = 13155431034330.

The previous prime is 13155431034293. The next prime is 13155431034353. The reversal of 13155431034331 is 13343013455131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13155431034331 - 211 = 13155431032283 is a prime.

It is a super-2 number, since 2×131554310343312 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13155431038331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6577715517165 + 6577715517166.

It is an arithmetic number, because the mean of its divisors is an integer number (6577715517166).

Almost surely, 213155431034331 is an apocalyptic number.

13155431034331 is a deficient number, since it is larger than the sum of its proper divisors (1).

13155431034331 is an equidigital number, since it uses as much as digits as its factorization.

13155431034331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 97200, while the sum is 37.

Adding to 13155431034331 its reverse (13343013455131), we get a palindrome (26498444489462).

The spelling of 13155431034331 in words is "thirteen trillion, one hundred fifty-five billion, four hundred thirty-one million, thirty-four thousand, three hundred thirty-one".