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13158100468033 = 97135650520289
BaseRepresentation
bin1011111101111001101111…
…1001111000000101000001
31201120220100122102110021121
42333132123321320011001
53211040242204434113
643552425314152241
72525432665404463
oct277363371700501
951526318373247
1013158100468033
114213356757424
121586165282681
13745a5a526511
14336bd9554133
1517c4144a9e8d
hexbf79be78141

13158100468033 has 4 divisors (see below), whose sum is σ = 13293750988420. Its totient is φ = 13022449947648.

The previous prime is 13158100468027. The next prime is 13158100468057. The reversal of 13158100468033 is 33086400185131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 8972708720704 + 4185391747329 = 2995448^2 + 2045823^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13158100468033 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13158100468003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 67825260048 + ... + 67825260241.

It is an arithmetic number, because the mean of its divisors is an integer number (3323437747105).

Almost surely, 213158100468033 is an apocalyptic number.

It is an amenable number.

13158100468033 is a deficient number, since it is larger than the sum of its proper divisors (135650520387).

13158100468033 is an equidigital number, since it uses as much as digits as its factorization.

13158100468033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 135650520386.

The product of its (nonzero) digits is 207360, while the sum is 43.

The spelling of 13158100468033 in words is "thirteen trillion, one hundred fifty-eight billion, one hundred million, four hundred sixty-eight thousand, thirty-three".

Divisors: 1 97 135650520289 13158100468033