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13158405473 is a prime number
BaseRepresentation
bin11000100000100110…
…10101010101100001
31020222000212020220212
430100103111111201
5203422022433343
610013410143505
7644035413113
oct142023252541
936860766825
1013158405473
115642638874
122672881b95
131319154755
148cb8013b3
155202e1c18
hex3104d5561

13158405473 has 2 divisors, whose sum is σ = 13158405474. Its totient is φ = 13158405472.

The previous prime is 13158405457. The next prime is 13158405487. The reversal of 13158405473 is 37450485131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11567432704 + 1590972769 = 107552^2 + 39887^2 .

It is a cyclic number.

It is not a de Polignac number, because 13158405473 - 24 = 13158405457 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13158405473.

It is not a weakly prime, because it can be changed into another prime (13158404473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6579202736 + 6579202737.

It is an arithmetic number, because the mean of its divisors is an integer number (6579202737).

Almost surely, 213158405473 is an apocalyptic number.

It is an amenable number.

13158405473 is a deficient number, since it is larger than the sum of its proper divisors (1).

13158405473 is an equidigital number, since it uses as much as digits as its factorization.

13158405473 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 201600, while the sum is 41.

The spelling of 13158405473 in words is "thirteen billion, one hundred fifty-eight million, four hundred five thousand, four hundred seventy-three".