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13158618493441 = 31094232427949
BaseRepresentation
bin1011111101111011101011…
…0001111111001000000001
31201120221200202011212112211
42333132322301333020001
53211042322313242231
643552552541222121
72525451555504601
oct277367261771001
951527622155484
1013158618493441
1142135a21055a3
12158628a861941
13745b10950025
14336c4827cc01
1517c444bd3eb1
hexbf7bac7f201

13158618493441 has 4 divisors (see below), whose sum is σ = 13162850924500. Its totient is φ = 13154386062384.

The previous prime is 13158618493399. The next prime is 13158618493451. The reversal of 13158618493441 is 14439481685131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3840831718416 + 9317786775025 = 1959804^2 + 3052505^2 .

It is a cyclic number.

It is not a de Polignac number, because 13158618493441 - 213 = 13158618485249 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13158618493451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2116210866 + ... + 2116217083.

It is an arithmetic number, because the mean of its divisors is an integer number (3290712731125).

Almost surely, 213158618493441 is an apocalyptic number.

It is an amenable number.

13158618493441 is a deficient number, since it is larger than the sum of its proper divisors (4232431059).

13158618493441 is an equidigital number, since it uses as much as digits as its factorization.

13158618493441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4232431058.

The product of its digits is 9953280, while the sum is 58.

The spelling of 13158618493441 in words is "thirteen trillion, one hundred fifty-eight billion, six hundred eighteen million, four hundred ninety-three thousand, four hundred forty-one".

Divisors: 1 3109 4232427949 13158618493441