Base | Representation |
---|---|
bin | 10011001001101010001… |
… | …011001100101111110011 |
3 | 11122210221011220121011202 |
4 | 103021222023030233303 |
5 | 133030223034011032 |
6 | 2444325300401415 |
7 | 164036505406502 |
oct | 23115213145763 |
9 | 4583834817152 |
10 | 1316041313267 |
11 | 46814801528a |
12 | 1930836a626b |
13 | 971435b6b95 |
14 | 479a7bd2839 |
15 | 2437737bd62 |
hex | 1326a2ccbf3 |
1316041313267 has 2 divisors, whose sum is σ = 1316041313268. Its totient is φ = 1316041313266.
The previous prime is 1316041313219. The next prime is 1316041313281. The reversal of 1316041313267 is 7623131406131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1316041313267 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1316041313267.
It is not a weakly prime, because it can be changed into another prime (1316041313467) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 658020656633 + 658020656634.
It is an arithmetic number, because the mean of its divisors is an integer number (658020656634).
Almost surely, 21316041313267 is an apocalyptic number.
1316041313267 is a deficient number, since it is larger than the sum of its proper divisors (1).
1316041313267 is an equidigital number, since it uses as much as digits as its factorization.
1316041313267 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54432, while the sum is 38.
Adding to 1316041313267 its reverse (7623131406131), we get a palindrome (8939172719398).
The spelling of 1316041313267 in words is "one trillion, three hundred sixteen billion, forty-one million, three hundred thirteen thousand, two hundred sixty-seven".
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