Base | Representation |
---|---|
bin | 1011111110000010100111… |
… | …1001001110110101001001 |
3 | 1201121010111122221112110201 |
4 | 2333200221321032311021 |
5 | 3211110132030220003 |
6 | 43553501533012201 |
7 | 2525546012625505 |
oct | 277405171166511 |
9 | 51533448845421 |
10 | 13160482663753 |
11 | 4214369409317 |
12 | 158670b024061 |
13 | 746049c1a299 |
14 | 336d83a9b305 |
15 | 17c5036b5b1d |
hex | bf829e4ed49 |
13160482663753 has 2 divisors, whose sum is σ = 13160482663754. Its totient is φ = 13160482663752.
The previous prime is 13160482663619. The next prime is 13160482663759. The reversal of 13160482663753 is 35736628406131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6851604648249 + 6308878015504 = 2617557^2 + 2511748^2 .
It is a cyclic number.
It is not a de Polignac number, because 13160482663753 - 221 = 13160480566601 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13160482663694 and 13160482663703.
It is not a weakly prime, because it can be changed into another prime (13160482663759) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6580241331876 + 6580241331877.
It is an arithmetic number, because the mean of its divisors is an integer number (6580241331877).
Almost surely, 213160482663753 is an apocalyptic number.
It is an amenable number.
13160482663753 is a deficient number, since it is larger than the sum of its proper divisors (1).
13160482663753 is an equidigital number, since it uses as much as digits as its factorization.
13160482663753 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13063680, while the sum is 55.
The spelling of 13160482663753 in words is "thirteen trillion, one hundred sixty billion, four hundred eighty-two million, six hundred sixty-three thousand, seven hundred fifty-three".
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