Base | Representation |
---|---|
bin | 11000100000111010… |
… | …00000010011000011 |
3 | 1020222012122001122121 |
4 | 30100131000103003 |
5 | 203423200100424 |
6 | 10013540345111 |
7 | 644066102422 |
oct | 142035002303 |
9 | 36865561577 |
10 | 13160940739 |
11 | 564400a631 |
12 | 26736a5197 |
13 | 13198316cb |
14 | 8cbca12b9 |
15 | 520642ee4 |
hex | 3107404c3 |
13160940739 has 2 divisors, whose sum is σ = 13160940740. Its totient is φ = 13160940738.
The previous prime is 13160940731. The next prime is 13160940763. The reversal of 13160940739 is 93704906131.
It is a weak prime.
It is an emirp because it is prime and its reverse (93704906131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13160940739 - 23 = 13160940731 is a prime.
It is a super-2 number, since 2×131609407392 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13160940695 and 13160940704.
It is not a weakly prime, because it can be changed into another prime (13160940731) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6580470369 + 6580470370.
It is an arithmetic number, because the mean of its divisors is an integer number (6580470370).
Almost surely, 213160940739 is an apocalyptic number.
13160940739 is a deficient number, since it is larger than the sum of its proper divisors (1).
13160940739 is an equidigital number, since it uses as much as digits as its factorization.
13160940739 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 122472, while the sum is 43.
The spelling of 13160940739 in words is "thirteen billion, one hundred sixty million, nine hundred forty thousand, seven hundred thirty-nine".
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