Base | Representation |
---|---|
bin | 11000100001000000… |
… | …11101101010011001 |
3 | 1020222021100010102110 |
4 | 30100200131222121 |
5 | 203423413104244 |
6 | 10014012022533 |
7 | 644106600042 |
oct | 142040355231 |
9 | 36867303373 |
10 | 13161847449 |
11 | 5644579883 |
12 | 2673a61a49 |
13 | 1319a8b31a |
14 | 8cc0598c9 |
15 | 5207719b9 |
hex | 31081da99 |
13161847449 has 4 divisors (see below), whose sum is σ = 17549129936. Its totient is φ = 8774564964.
The previous prime is 13161847441. The next prime is 13161847549. The reversal of 13161847449 is 94474816131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 13161847449 - 23 = 13161847441 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13161847398 and 13161847407.
It is not an unprimeable number, because it can be changed into a prime (13161847441) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2193641239 + ... + 2193641244.
It is an arithmetic number, because the mean of its divisors is an integer number (4387282484).
Almost surely, 213161847449 is an apocalyptic number.
It is an amenable number.
13161847449 is a deficient number, since it is larger than the sum of its proper divisors (4387282487).
13161847449 is an equidigital number, since it uses as much as digits as its factorization.
13161847449 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4387282486.
The product of its digits is 580608, while the sum is 48.
The spelling of 13161847449 in words is "thirteen billion, one hundred sixty-one million, eight hundred forty-seven thousand, four hundred forty-nine".
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