Base | Representation |
---|---|
bin | 1011111110001101001000… |
… | …1011111111010001011011 |
3 | 1201121101210102211122122102 |
4 | 2333203102023333101123 |
5 | 3211131422333344201 |
6 | 43555050034114015 |
7 | 2526005666114645 |
oct | 277432213772133 |
9 | 51541712748572 |
10 | 13163306153051 |
11 | 421558817a64a |
12 | 158717871b90b |
13 | 7463a9b7cc02 |
14 | 337170a77895 |
15 | 17c61b4e026b |
hex | bf8d22ff45b |
13163306153051 has 4 divisors (see below), whose sum is σ = 13165337220504. Its totient is φ = 13161275085600.
The previous prime is 13163306153027. The next prime is 13163306153069. The reversal of 13163306153051 is 15035160336131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13163306153051 - 214 = 13163306136667 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13163306152996 and 13163306153014.
It is not an unprimeable number, because it can be changed into a prime (13163306143051) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1015524005 + ... + 1015536966.
It is an arithmetic number, because the mean of its divisors is an integer number (3291334305126).
Almost surely, 213163306153051 is an apocalyptic number.
13163306153051 is a deficient number, since it is larger than the sum of its proper divisors (2031067453).
13163306153051 is an equidigital number, since it uses as much as digits as its factorization.
13163306153051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2031067452.
The product of its (nonzero) digits is 72900, while the sum is 38.
Adding to 13163306153051 its reverse (15035160336131), we get a palindrome (28198466489182).
The spelling of 13163306153051 in words is "thirteen trillion, one hundred sixty-three billion, three hundred six million, one hundred fifty-three thousand, fifty-one".
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