Base | Representation |
---|---|
bin | 1011111110001101100100… |
… | …0111011110111011110110 |
3 | 1201121102002112121020200012 |
4 | 2333203121013132323312 |
5 | 3211132142114200114 |
6 | 43555105350020222 |
7 | 2526011610236612 |
oct | 277433107367366 |
9 | 51542075536605 |
10 | 13163422412534 |
11 | 4215637867069 |
12 | 15871ab647672 |
13 | 7463c7c973c4 |
14 | 33718229c342 |
15 | 17c62680763e |
hex | bf8d91deef6 |
13163422412534 has 16 divisors (see below), whose sum is σ = 19750571056656. Its totient is φ = 6579898936800.
The previous prime is 13163422412527. The next prime is 13163422412629. The reversal of 13163422412534 is 43521422436131.
It is a super-2 number, since 2×131634224125342 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13163422412491 and 13163422412500.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 156020549 + ... + 156104895.
It is an arithmetic number, because the mean of its divisors is an integer number (1234410691041).
Almost surely, 213163422412534 is an apocalyptic number.
13163422412534 is a deficient number, since it is larger than the sum of its proper divisors (6587148644122).
13163422412534 is a wasteful number, since it uses less digits than its factorization.
13163422412534 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 104911.
The product of its digits is 414720, while the sum is 41.
Adding to 13163422412534 its reverse (43521422436131), we get a palindrome (56684844848665).
The spelling of 13163422412534 in words is "thirteen trillion, one hundred sixty-three billion, four hundred twenty-two million, four hundred twelve thousand, five hundred thirty-four".
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