Base | Representation |
---|---|
bin | 11000100001001101… |
… | …00010011111110001 |
3 | 1020222101100001011000 |
4 | 30100212202133301 |
5 | 203424320040423 |
6 | 10014110112213 |
7 | 644126252265 |
oct | 142046423761 |
9 | 36871301130 |
10 | 13163440113 |
11 | 564546742a |
12 | 26744ab669 |
13 | 131a1c8225 |
14 | 8cc3520a5 |
15 | 520988843 |
hex | 3109a27f1 |
13163440113 has 8 divisors (see below), whose sum is σ = 19501392800. Its totient is φ = 8775626724.
The previous prime is 13163440097. The next prime is 13163440127. The reversal of 13163440113 is 31104436131.
13163440113 is a `hidden beast` number, since 1 + 316 + 344 + 0 + 1 + 1 + 3 = 666.
It is not a de Polignac number, because 13163440113 - 24 = 13163440097 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27), and also a Moran number because the ratio is a prime number: 487534819 = 13163440113 / (1 + 3 + 1 + 6 + 3 + 4 + 4 + 0 + 1 + 1 + 3).
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13163440163) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 243767383 + ... + 243767436.
It is an arithmetic number, because the mean of its divisors is an integer number (2437674100).
Almost surely, 213163440113 is an apocalyptic number.
It is an amenable number.
13163440113 is a deficient number, since it is larger than the sum of its proper divisors (6337952687).
13163440113 is an equidigital number, since it uses as much as digits as its factorization.
13163440113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 487534828 (or 487534822 counting only the distinct ones).
The product of its (nonzero) digits is 2592, while the sum is 27.
Adding to 13163440113 its reverse (31104436131), we get a palindrome (44267876244).
The spelling of 13163440113 in words is "thirteen billion, one hundred sixty-three million, four hundred forty thousand, one hundred thirteen".
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