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1316413000561 = 4330614255827
BaseRepresentation
bin10011001010000000010…
…101000100101101110001
311122211220002022021021211
4103022000111010231301
5133032003212004221
62444430215120121
7164051640611101
oct23120025045561
94584802267254
101316413000561
1146831890246a
12193168073041
13971a25c44a9
1447a01307201
1524399ceb6e1
hex13280544b71

1316413000561 has 4 divisors (see below), whose sum is σ = 1347027256432. Its totient is φ = 1285798744692.

The previous prime is 1316413000453. The next prime is 1316413000571. The reversal of 1316413000561 is 1650003146131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1316413000561 - 211 = 1316412998513 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1316413000571) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15307127871 + ... + 15307127956.

It is an arithmetic number, because the mean of its divisors is an integer number (336756814108).

Almost surely, 21316413000561 is an apocalyptic number.

It is an amenable number.

1316413000561 is a deficient number, since it is larger than the sum of its proper divisors (30614255871).

1316413000561 is an equidigital number, since it uses as much as digits as its factorization.

1316413000561 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30614255870.

The product of its (nonzero) digits is 6480, while the sum is 31.

Adding to 1316413000561 its reverse (1650003146131), we get a palindrome (2966416146692).

The spelling of 1316413000561 in words is "one trillion, three hundred sixteen billion, four hundred thirteen million, five hundred sixty-one", and thus it is an aban number.

Divisors: 1 43 30614255827 1316413000561