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13166633400097 is a prime number
BaseRepresentation
bin1011111110011001100010…
…0000011011011100100001
31201121201101022122022112111
42333212120200123130201
53211210231122300342
644000400132355321
72526154310211442
oct277463040333441
951551338568474
1013166633400097
114216a353345a1
121587946a75b41
137467ba2b2148
143373a89072c9
1517c763676217
hexbf99881b721

13166633400097 has 2 divisors, whose sum is σ = 13166633400098. Its totient is φ = 13166633400096.

The previous prime is 13166633400029. The next prime is 13166633400103. The reversal of 13166633400097 is 79000433666131.

13166633400097 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7339932611361 + 5826700788736 = 2709231^2 + 2413856^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13166633400097 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13166633400097.

It is not a weakly prime, because it can be changed into another prime (13166633400007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6583316700048 + 6583316700049.

It is an arithmetic number, because the mean of its divisors is an integer number (6583316700049).

Almost surely, 213166633400097 is an apocalyptic number.

It is an amenable number.

13166633400097 is a deficient number, since it is larger than the sum of its proper divisors (1).

13166633400097 is an equidigital number, since it uses as much as digits as its factorization.

13166633400097 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1469664, while the sum is 49.

The spelling of 13166633400097 in words is "thirteen trillion, one hundred sixty-six billion, six hundred thirty-three million, four hundred thousand, ninety-seven".