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1317000356753 is a prime number
BaseRepresentation
bin10011001010100011010…
…101101010001110010001
311122220102000112001111212
4103022203111222032101
5133034204042404003
62445004400145505
7164102332216604
oct23124325521621
94586360461455
101317000356753
1146859a404904
121932b0908295
13972671b4033
1447a5931c33b
15243d166cdd8
hex132a356a391

1317000356753 has 2 divisors, whose sum is σ = 1317000356754. Its totient is φ = 1317000356752.

The previous prime is 1317000356699. The next prime is 1317000356759. The reversal of 1317000356753 is 3576530007131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 717261629569 + 599738727184 = 846913^2 + 774428^2 .

It is an emirp because it is prime and its reverse (3576530007131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1317000356753 - 210 = 1317000355729 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1317000356753.

It is not a weakly prime, because it can be changed into another prime (1317000356759) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 658500178376 + 658500178377.

It is an arithmetic number, because the mean of its divisors is an integer number (658500178377).

Almost surely, 21317000356753 is an apocalyptic number.

It is an amenable number.

1317000356753 is a deficient number, since it is larger than the sum of its proper divisors (1).

1317000356753 is an equidigital number, since it uses as much as digits as its factorization.

1317000356753 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 198450, while the sum is 41.

The spelling of 1317000356753 in words is "one trillion, three hundred seventeen billion, three hundred fifty-six thousand, seven hundred fifty-three".