Base | Representation |
---|---|
bin | 11000100010001000… |
… | …11110111110001001 |
3 | 1020222221002212011022 |
4 | 30101010132332021 |
5 | 203433322234433 |
6 | 10014550242225 |
7 | 644253055241 |
oct | 142104367611 |
9 | 36887085138 |
10 | 13171289993 |
11 | 5649939134 |
12 | 2677056375 |
13 | 131ba16224 |
14 | 8cd3d6b21 |
15 | 5214d9698 |
hex | 31111ef89 |
13171289993 has 2 divisors, whose sum is σ = 13171289994. Its totient is φ = 13171289992.
The previous prime is 13171289983. The next prime is 13171290043. The reversal of 13171289993 is 39998217131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11878384144 + 1292905849 = 108988^2 + 35957^2 .
It is a cyclic number.
It is not a de Polignac number, because 13171289993 - 210 = 13171288969 is a prime.
It is not a weakly prime, because it can be changed into another prime (13171289983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6585644996 + 6585644997.
It is an arithmetic number, because the mean of its divisors is an integer number (6585644997).
Almost surely, 213171289993 is an apocalyptic number.
It is an amenable number.
13171289993 is a deficient number, since it is larger than the sum of its proper divisors (1).
13171289993 is an equidigital number, since it uses as much as digits as its factorization.
13171289993 is an evil number, because the sum of its binary digits is even.
The product of its digits is 734832, while the sum is 53.
The spelling of 13171289993 in words is "thirteen billion, one hundred seventy-one million, two hundred eighty-nine thousand, nine hundred ninety-three".
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