Base | Representation |
---|---|
bin | 111101010101010110… |
… | …1010001101011100001 |
3 | 110120222022021101202012 |
4 | 1322222231101223201 |
5 | 4124222012430442 |
6 | 140301431002305 |
7 | 12341654102501 |
oct | 1725255215341 |
9 | 416868241665 |
10 | 131713014497 |
11 | 5094a621299 |
12 | 2163a509395 |
13 | c560a59a8c |
14 | 6536bbba01 |
15 | 365d438582 |
hex | 1eaab51ae1 |
131713014497 has 2 divisors, whose sum is σ = 131713014498. Its totient is φ = 131713014496.
The previous prime is 131713014473. The next prime is 131713014527. The reversal of 131713014497 is 794410317131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 128912593936 + 2800420561 = 359044^2 + 52919^2 .
It is a cyclic number.
It is not a de Polignac number, because 131713014497 - 220 = 131711965921 is a prime.
It is not a weakly prime, because it can be changed into another prime (131713014457) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65856507248 + 65856507249.
It is an arithmetic number, because the mean of its divisors is an integer number (65856507249).
Almost surely, 2131713014497 is an apocalyptic number.
It is an amenable number.
131713014497 is a deficient number, since it is larger than the sum of its proper divisors (1).
131713014497 is an equidigital number, since it uses as much as digits as its factorization.
131713014497 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 63504, while the sum is 41.
The spelling of 131713014497 in words is "one hundred thirty-one billion, seven hundred thirteen million, fourteen thousand, four hundred ninety-seven".
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