Base | Representation |
---|---|
bin | 111101010110000100… |
… | …0111011010100100001 |
3 | 110121000222111000202121 |
4 | 1322230020323110201 |
5 | 4124244140241121 |
6 | 140304045544241 |
7 | 12342365236246 |
oct | 1725410732441 |
9 | 417028430677 |
10 | 131737040161 |
11 | 50962141111 |
12 | 21646575081 |
13 | c565a1c64c |
14 | 653a0735cd |
15 | 36605d2141 |
hex | 1eac23b521 |
131737040161 has 2 divisors, whose sum is σ = 131737040162. Its totient is φ = 131737040160.
The previous prime is 131737040147. The next prime is 131737040173. The reversal of 131737040161 is 161040737131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 93173899536 + 38563140625 = 305244^2 + 196375^2 .
It is a cyclic number.
It is not a de Polignac number, because 131737040161 - 25 = 131737040129 is a prime.
It is not a weakly prime, because it can be changed into another prime (131737010161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65868520080 + 65868520081.
It is an arithmetic number, because the mean of its divisors is an integer number (65868520081).
Almost surely, 2131737040161 is an apocalyptic number.
It is an amenable number.
131737040161 is a deficient number, since it is larger than the sum of its proper divisors (1).
131737040161 is an equidigital number, since it uses as much as digits as its factorization.
131737040161 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10584, while the sum is 34.
Adding to 131737040161 its reverse (161040737131), we get a palindrome (292777777292).
It can be divided in two parts, 1317370 and 40161, that added together give a palindrome (1357531).
The spelling of 131737040161 in words is "one hundred thirty-one billion, seven hundred thirty-seven million, forty thousand, one hundred sixty-one".
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