Base | Representation |
---|---|
bin | 11101111101000101000110… |
… | …100111110110001010011001 |
3 | 122021110021211001121211120211 |
4 | 131331011012213312022121 |
5 | 114231414441440031133 |
6 | 1144104503314251121 |
7 | 36514644525540025 |
oct | 3575050647661231 |
9 | 567407731554524 |
10 | 131740716720793 |
11 | 38a81a1912a794 |
12 | 12938297586aa1 |
13 | 58681336b524b |
14 | 24763db365385 |
15 | 1036d29775bcd |
hex | 77d1469f6299 |
131740716720793 has 2 divisors, whose sum is σ = 131740716720794. Its totient is φ = 131740716720792.
The previous prime is 131740716720703. The next prime is 131740716720827. The reversal of 131740716720793 is 397027617047131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 131214550731664 + 526165989129 = 11454892^2 + 725373^2 .
It is a cyclic number.
It is not a de Polignac number, because 131740716720793 - 217 = 131740716589721 is a prime.
It is not a weakly prime, because it can be changed into another prime (131740716720703) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65870358360396 + 65870358360397.
It is an arithmetic number, because the mean of its divisors is an integer number (65870358360397).
Almost surely, 2131740716720793 is an apocalyptic number.
It is an amenable number.
131740716720793 is a deficient number, since it is larger than the sum of its proper divisors (1).
131740716720793 is an equidigital number, since it uses as much as digits as its factorization.
131740716720793 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9335088, while the sum is 58.
The spelling of 131740716720793 in words is "one hundred thirty-one trillion, seven hundred forty billion, seven hundred sixteen million, seven hundred twenty thousand, seven hundred ninety-three".
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