Base | Representation |
---|---|
bin | 11000100010100010… |
… | …10101100001000001 |
3 | 1021000011110000202102 |
4 | 30101101111201001 |
5 | 203440203043022 |
6 | 10015150400145 |
7 | 644323516643 |
oct | 142121254101 |
9 | 37004400672 |
10 | 13174659137 |
11 | 565082a452 |
12 | 2678200055 |
13 | 131c6258c3 |
14 | 8cda32893 |
15 | 521952a92 |
hex | 311455841 |
13174659137 has 2 divisors, whose sum is σ = 13174659138. Its totient is φ = 13174659136.
The previous prime is 13174659073. The next prime is 13174659149. The reversal of 13174659137 is 73195647131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12695880976 + 478778161 = 112676^2 + 21881^2 .
It is a cyclic number.
It is not a de Polignac number, because 13174659137 - 26 = 13174659073 is a prime.
It is a super-2 number, since 2×131746591372 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13174659091 and 13174659100.
It is not a weakly prime, because it can be changed into another prime (13174629137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6587329568 + 6587329569.
It is an arithmetic number, because the mean of its divisors is an integer number (6587329569).
Almost surely, 213174659137 is an apocalyptic number.
It is an amenable number.
13174659137 is a deficient number, since it is larger than the sum of its proper divisors (1).
13174659137 is an equidigital number, since it uses as much as digits as its factorization.
13174659137 is an evil number, because the sum of its binary digits is even.
The product of its digits is 476280, while the sum is 47.
The spelling of 13174659137 in words is "thirteen billion, one hundred seventy-four million, six hundred fifty-nine thousand, one hundred thirty-seven".
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