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131750021643089 is a prime number
BaseRepresentation
bin11101111101001101110001…
…001111010011101101010001
3122021111011211112110212100112
4131331031301033103231101
5114232043021020034324
61144113042511131105
736515424233221253
oct3575156117235521
9567434745425315
10131750021643089
1138a85963557613
121293a053813a95
135868c87397925
142476a41071cd3
1510371c15d4c0e
hex77d3713d3b51

131750021643089 has 2 divisors, whose sum is σ = 131750021643090. Its totient is φ = 131750021643088.

The previous prime is 131750021643011. The next prime is 131750021643131. The reversal of 131750021643089 is 980346120057131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 75867444676864 + 55882576966225 = 8710192^2 + 7475465^2 .

It is an emirp because it is prime and its reverse (980346120057131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131750021643089 - 236 = 131681302166353 is a prime.

It is not a weakly prime, because it can be changed into another prime (131750021643389) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65875010821544 + 65875010821545.

It is an arithmetic number, because the mean of its divisors is an integer number (65875010821545).

It is a 1-persistent number, because it is pandigital, but 2⋅131750021643089 = 263500043286178 is not.

Almost surely, 2131750021643089 is an apocalyptic number.

It is an amenable number.

131750021643089 is a deficient number, since it is larger than the sum of its proper divisors (1).

131750021643089 is an equidigital number, since it uses as much as digits as its factorization.

131750021643089 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1088640, while the sum is 50.

The spelling of 131750021643089 in words is "one hundred thirty-one trillion, seven hundred fifty billion, twenty-one million, six hundred forty-three thousand, eighty-nine".