Base | Representation |
---|---|
bin | 11101111101001110001001… |
… | …101111100100111100111010 |
3 | 122021111012220012001112120122 |
4 | 131331032021233210330322 |
5 | 114232044341241134024 |
6 | 1144113151354453242 |
7 | 36515440354504616 |
oct | 3575161157447472 |
9 | 567435805045518 |
10 | 131750432755514 |
11 | 38a86054622451 |
12 | 1293a149434222 |
13 | 58690215ca211 |
14 | 2476a7d8ca346 |
15 | 10371e7740d5e |
hex | 77d389be4f3a |
131750432755514 has 4 divisors (see below), whose sum is σ = 197625649133274. Its totient is φ = 65875216377756.
The previous prime is 131750432755477. The next prime is 131750432755561. The reversal of 131750432755514 is 415557234057131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 73835060409289 + 57915372346225 = 8592733^2 + 7610215^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32937608188877 + ... + 32937608188880.
Almost surely, 2131750432755514 is an apocalyptic number.
131750432755514 is a deficient number, since it is larger than the sum of its proper divisors (65875216377760).
131750432755514 is an equidigital number, since it uses as much as digits as its factorization.
131750432755514 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65875216377759.
The product of its (nonzero) digits is 8820000, while the sum is 53.
The spelling of 131750432755514 in words is "one hundred thirty-one trillion, seven hundred fifty billion, four hundred thirty-two million, seven hundred fifty-five thousand, five hundred fourteen".
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