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131817646481 is a prime number
BaseRepresentation
bin111101011000011110…
…0011010100110010001
3110121020121011020211212
41322300330122212101
54124430304141411
6140320045345505
712344364336143
oct1726074324621
9417217136755
10131817646481
11509a3696904
1221669568295
13c5796329b1
146546a56c93
15366770568b
hex1eb0f1a991

131817646481 has 2 divisors, whose sum is σ = 131817646482. Its totient is φ = 131817646480.

The previous prime is 131817646463. The next prime is 131817646537. The reversal of 131817646481 is 184646718131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 131536782400 + 280864081 = 362680^2 + 16759^2 .

It is a cyclic number.

It is not a de Polignac number, because 131817646481 - 234 = 114637777297 is a prime.

It is a super-2 number, since 2×1318176464812 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131817646381) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65908823240 + 65908823241.

It is an arithmetic number, because the mean of its divisors is an integer number (65908823241).

Almost surely, 2131817646481 is an apocalyptic number.

It is an amenable number.

131817646481 is a deficient number, since it is larger than the sum of its proper divisors (1).

131817646481 is an equidigital number, since it uses as much as digits as its factorization.

131817646481 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 774144, while the sum is 50.

The spelling of 131817646481 in words is "one hundred thirty-one billion, eight hundred seventeen million, six hundred forty-six thousand, four hundred eighty-one".