Base | Representation |
---|---|
bin | 1011111111100001001011… |
… | …1111010011101110100011 |
3 | 1201200120000211021121022012 |
4 | 2333320102333103232203 |
5 | 3212014124223400413 |
6 | 44013300524503135 |
7 | 2530435051165151 |
oct | 277702277235643 |
9 | 51616024247265 |
10 | 13185868184483 |
11 | 4224105920815 |
12 | 158b6146aaaab |
13 | 748564295777 |
14 | 3382b131a3d1 |
15 | 17cedc13b7a8 |
hex | bfe12fd3ba3 |
13185868184483 has 2 divisors, whose sum is σ = 13185868184484. Its totient is φ = 13185868184482.
The previous prime is 13185868184381. The next prime is 13185868184539. The reversal of 13185868184483 is 38448186858131.
It is a strong prime.
It is an emirp because it is prime and its reverse (38448186858131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13185868184483 - 210 = 13185868183459 is a prime.
It is a super-2 number, since 2×131858681844832 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13185868181483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6592934092241 + 6592934092242.
It is an arithmetic number, because the mean of its divisors is an integer number (6592934092242).
Almost surely, 213185868184483 is an apocalyptic number.
13185868184483 is a deficient number, since it is larger than the sum of its proper divisors (1).
13185868184483 is an equidigital number, since it uses as much as digits as its factorization.
13185868184483 is an evil number, because the sum of its binary digits is even.
The product of its digits is 141557760, while the sum is 68.
The spelling of 13185868184483 in words is "thirteen trillion, one hundred eighty-five billion, eight hundred sixty-eight million, one hundred eighty-four thousand, four hundred eighty-three".
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