Base | Representation |
---|---|
bin | 11000100100011010… |
… | …10011101010001001 |
3 | 1021001021000201221212 |
4 | 30102031103222021 |
5 | 204003214131134 |
6 | 10020511342505 |
7 | 644604244601 |
oct | 142215235211 |
9 | 37037021855 |
10 | 13190380169 |
11 | 565969793a |
12 | 2681521a35 |
13 | 132296b4a5 |
14 | 8d1b65c01 |
15 | 52300abce |
hex | 312353a89 |
13190380169 has 4 divisors (see below), whose sum is σ = 13349300496. Its totient is φ = 13031459844.
The previous prime is 13190380163. The next prime is 13190380171. The reversal of 13190380169 is 96108309131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 96108309131 = 2549 ⋅37704319.
It is a cyclic number.
It is not a de Polignac number, because 13190380169 - 24 = 13190380153 is a prime.
It is a super-2 number, since 2×131903801692 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13190380163) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 79460039 + ... + 79460204.
It is an arithmetic number, because the mean of its divisors is an integer number (3337325124).
Almost surely, 213190380169 is an apocalyptic number.
It is an amenable number.
13190380169 is a deficient number, since it is larger than the sum of its proper divisors (158920327).
13190380169 is an equidigital number, since it uses as much as digits as its factorization.
13190380169 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 158920326.
The product of its (nonzero) digits is 34992, while the sum is 41.
The spelling of 13190380169 in words is "thirteen billion, one hundred ninety million, three hundred eighty thousand, one hundred sixty-nine".
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