Base | Representation |
---|---|
bin | 11101111111011110001000… |
… | …101000111101000001011001 |
3 | 122022000222221112210222001212 |
4 | 131333132020220331001121 |
5 | 114242113001431031122 |
6 | 1144312200255552505 |
7 | 36532552453446545 |
oct | 3577361050750131 |
9 | 568028845728055 |
10 | 131905033064537 |
11 | 39035679453887 |
12 | 129640b482b735 |
13 | 587a78bc74505 |
14 | 2480348218a25 |
15 | 103b245124ce2 |
hex | 77f788a3d059 |
131905033064537 has 2 divisors, whose sum is σ = 131905033064538. Its totient is φ = 131905033064536.
The previous prime is 131905033064509. The next prime is 131905033064543. The reversal of 131905033064537 is 735460330509131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 131538052752016 + 366980312521 = 11469004^2 + 605789^2 .
It is a cyclic number.
It is not a de Polignac number, because 131905033064537 - 26 = 131905033064473 is a prime.
It is not a weakly prime, because it can be changed into another prime (131905023064537) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65952516532268 + 65952516532269.
It is an arithmetic number, because the mean of its divisors is an integer number (65952516532269).
Almost surely, 2131905033064537 is an apocalyptic number.
It is an amenable number.
131905033064537 is a deficient number, since it is larger than the sum of its proper divisors (1).
131905033064537 is an equidigital number, since it uses as much as digits as its factorization.
131905033064537 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3061800, while the sum is 50.
The spelling of 131905033064537 in words is "one hundred thirty-one trillion, nine hundred five billion, thirty-three million, sixty-four thousand, five hundred thirty-seven".
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