Base | Representation |
---|---|
bin | 1011111111110100100110… |
… | …1111001101000001000011 |
3 | 1201201001111011101110100201 |
4 | 2333331021233031001003 |
5 | 3212110313402124432 |
6 | 44015522124030031 |
7 | 2531011205143333 |
oct | 277751157150103 |
9 | 51631434343321 |
10 | 13191081676867 |
11 | 4226340796806 |
12 | 159062a692317 |
13 | 748bb54239c3 |
14 | 3386478b30c3 |
15 | 17d1e4bb4ee7 |
hex | bff49bcd043 |
13191081676867 has 2 divisors, whose sum is σ = 13191081676868. Its totient is φ = 13191081676866.
The previous prime is 13191081676837. The next prime is 13191081676879. The reversal of 13191081676867 is 76867618019131.
It is a strong prime.
It is an emirp because it is prime and its reverse (76867618019131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13191081676867 - 211 = 13191081674819 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13191081676799 and 13191081676808.
It is not a weakly prime, because it can be changed into another prime (13191081676837) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6595540838433 + 6595540838434.
It is an arithmetic number, because the mean of its divisors is an integer number (6595540838434).
Almost surely, 213191081676867 is an apocalyptic number.
13191081676867 is a deficient number, since it is larger than the sum of its proper divisors (1).
13191081676867 is an equidigital number, since it uses as much as digits as its factorization.
13191081676867 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18289152, while the sum is 64.
The spelling of 13191081676867 in words is "thirteen trillion, one hundred ninety-one billion, eighty-one million, six hundred seventy-six thousand, eight hundred sixty-seven".
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