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13195013201257 = 44632956534439
BaseRepresentation
bin1100000000000011010000…
…0100110001110101101001
31201201102122011020120221011
43000000310010301311221
53212141341334420012
644021412210143521
72531210504432506
oct300006404616551
951642564216834
1013195013201257
114227a78a60218
121591347281ba1
13749390abb6b4
143388dbac04ad
1517d374e111a7
hexc0034131d69

13195013201257 has 4 divisors (see below), whose sum is σ = 13197969740160. Its totient is φ = 13192056662356.

The previous prime is 13195013201239. The next prime is 13195013201317. The reversal of 13195013201257 is 75210231059131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13195013201257 - 27 = 13195013201129 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13195013201857) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1478262757 + ... + 1478271682.

It is an arithmetic number, because the mean of its divisors is an integer number (3299492435040).

Almost surely, 213195013201257 is an apocalyptic number.

It is an amenable number.

13195013201257 is a deficient number, since it is larger than the sum of its proper divisors (2956538903).

13195013201257 is an equidigital number, since it uses as much as digits as its factorization.

13195013201257 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2956538902.

The product of its (nonzero) digits is 56700, while the sum is 40.

The spelling of 13195013201257 in words is "thirteen trillion, one hundred ninety-five billion, thirteen million, two hundred one thousand, two hundred fifty-seven".

Divisors: 1 4463 2956534439 13195013201257