Base | Representation |
---|---|
bin | 11000100101000110… |
… | …00110101000010011 |
3 | 1021001122210000211011 |
4 | 30102203012220103 |
5 | 204011200001341 |
6 | 10021234031351 |
7 | 645003643114 |
oct | 142243065023 |
9 | 37048700734 |
10 | 13196093971 |
11 | 566193a795 |
12 | 2683418557 |
13 | 1323bbc138 |
14 | 8d281220b |
15 | 523788b81 |
hex | 3128c6a13 |
13196093971 has 2 divisors, whose sum is σ = 13196093972. Its totient is φ = 13196093970.
The previous prime is 13196093929. The next prime is 13196093983. The reversal of 13196093971 is 17939069131.
It is a strong prime.
It is an emirp because it is prime and its reverse (17939069131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13196093971 - 231 = 11048610323 is a prime.
It is not a weakly prime, because it can be changed into another prime (13196091971) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6598046985 + 6598046986.
It is an arithmetic number, because the mean of its divisors is an integer number (6598046986).
Almost surely, 213196093971 is an apocalyptic number.
13196093971 is a deficient number, since it is larger than the sum of its proper divisors (1).
13196093971 is an equidigital number, since it uses as much as digits as its factorization.
13196093971 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 275562, while the sum is 49.
The spelling of 13196093971 in words is "thirteen billion, one hundred ninety-six million, ninety-three thousand, nine hundred seventy-one".
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