13196175693793 has 4 divisors (see below), whose sum is σ = 13211537948080. Its totient is φ = 13180813439508.

The previous prime is 13196175693769. The next prime is 13196175693797. The reversal of 13196175693793 is 39739657169131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13196175693793 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13196175693797) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7681125855 + ... + 7681127572.

It is an arithmetic number, because the mean of its divisors is an integer number (3302884487020).

Almost surely, 2^{13196175693793} is an apocalyptic number.

It is an amenable number.

13196175693793 is a deficient number, since it is larger than the sum of its proper divisors (15362254287).

13196175693793 is an equidigital number, since it uses as much as digits as its factorization.

13196175693793 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15362254286.

The product of its digits is 173604060, while the sum is 70.

The spelling of 13196175693793 in words is "thirteen trillion, one hundred ninety-six billion, one hundred seventy-five million, six hundred ninety-three thousand, seven hundred ninety-three".