Base | Representation |
---|---|
bin | 10011001101010100010… |
… | …010000111010010110011 |
3 | 11200012001220112110220102 |
4 | 103031110102013102303 |
5 | 133111244030310413 |
6 | 2450215124303015 |
7 | 164236030221236 |
oct | 23152422072263 |
9 | 4605056473812 |
10 | 1319968994483 |
11 | 4698830a4317 |
12 | 19399ab41a6b |
13 | 9761b2374c9 |
14 | 47c5b6bd41d |
15 | 245070b9458 |
hex | 133544874b3 |
1319968994483 has 2 divisors, whose sum is σ = 1319968994484. Its totient is φ = 1319968994482.
The previous prime is 1319968994471. The next prime is 1319968994497. The reversal of 1319968994483 is 3844998699131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1319968994483 - 212 = 1319968990387 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1319968994483.
It is not a weakly prime, because it can be changed into another prime (1319968994083) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 659984497241 + 659984497242.
It is an arithmetic number, because the mean of its divisors is an integer number (659984497242).
Almost surely, 21319968994483 is an apocalyptic number.
1319968994483 is a deficient number, since it is larger than the sum of its proper divisors (1).
1319968994483 is an equidigital number, since it uses as much as digits as its factorization.
1319968994483 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 362797056, while the sum is 74.
The spelling of 1319968994483 in words is "one trillion, three hundred nineteen billion, nine hundred sixty-eight million, nine hundred ninety-four thousand, four hundred eighty-three".
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