Base | Representation |
---|---|
bin | 11110000000110101101100… |
… | …010111010000100010110011 |
3 | 122022100222121121101200221022 |
4 | 132000311230113100202303 |
5 | 114300133022233204441 |
6 | 1144423305301050055 |
7 | 36542421313652246 |
oct | 3600655427204263 |
9 | 568328547350838 |
10 | 131999047944371 |
11 | 390715333a1583 |
12 | 1297a3720b692b |
13 | 58865c27c7c1a |
14 | 2484b0642125d |
15 | 103d8e8bb584b |
hex | 780d6c5d08b3 |
131999047944371 has 2 divisors, whose sum is σ = 131999047944372. Its totient is φ = 131999047944370.
The previous prime is 131999047944319. The next prime is 131999047944431. The reversal of 131999047944371 is 173449740999131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131999047944371 - 26 = 131999047944307 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131999047944295 and 131999047944304.
It is not a weakly prime, because it can be changed into another prime (131999047944871) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65999523972185 + 65999523972186.
It is an arithmetic number, because the mean of its divisors is an integer number (65999523972186).
Almost surely, 2131999047944371 is an apocalyptic number.
131999047944371 is a deficient number, since it is larger than the sum of its proper divisors (1).
131999047944371 is an equidigital number, since it uses as much as digits as its factorization.
131999047944371 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 185177664, while the sum is 71.
The spelling of 131999047944371 in words is "one hundred thirty-one trillion, nine hundred ninety-nine billion, forty-seven million, nine hundred forty-four thousand, three hundred seventy-one".
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