Base | Representation |
---|---|
bin | 11110000000110110110010… |
… | …110101100110010111100011 |
3 | 122022101002200000012202100011 |
4 | 132000312302311212113203 |
5 | 114300142432424200303 |
6 | 1144424022455105351 |
7 | 36542462521564453 |
oct | 3600666265462743 |
9 | 568332600182304 |
10 | 132000230303203 |
11 | 39071a8a849239 |
12 | 1297a642072257 |
13 | 5886750753832 |
14 | 2484bb947bd63 |
15 | 103d9678b916d |
hex | 780db2d665e3 |
132000230303203 has 4 divisors (see below), whose sum is σ = 132000898683808. Its totient is φ = 131999561922600.
The previous prime is 132000230303197. The next prime is 132000230303213. The reversal of 132000230303203 is 302303032000231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132000230303203 - 241 = 129801207047651 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132000230303213) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 333893976 + ... + 334289077.
It is an arithmetic number, because the mean of its divisors is an integer number (33000224670952).
Almost surely, 2132000230303203 is an apocalyptic number.
132000230303203 is a deficient number, since it is larger than the sum of its proper divisors (668380605).
132000230303203 is an equidigital number, since it uses as much as digits as its factorization.
132000230303203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 668380604.
The product of its (nonzero) digits is 1944, while the sum is 22.
Adding to 132000230303203 its reverse (302303032000231), we get a palindrome (434303262303434).
The spelling of 132000230303203 in words is "one hundred thirty-two trillion, two hundred thirty million, three hundred three thousand, two hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •