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1320004120011 = 3440001373337
BaseRepresentation
bin10011001101010110011…
…000000110110111001011
311200012011100122001001220
4103031112120012313023
5133111332023320021
62450222421213123
7164236634615103
oct23152630066713
94605140561056
101320004120011
114698a0a05685
121939aa8611a3
13976255b5445
1447c62224203
152450a206cc6
hex13356606dcb

1320004120011 has 4 divisors (see below), whose sum is σ = 1760005493352. Its totient is φ = 880002746672.

The previous prime is 1320004120003. The next prime is 1320004120037. The reversal of 1320004120011 is 1100214000231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1320004120011 - 23 = 1320004120003 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1320004120091) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 220000686666 + ... + 220000686671.

It is an arithmetic number, because the mean of its divisors is an integer number (440001373338).

Almost surely, 21320004120011 is an apocalyptic number.

1320004120011 is a deficient number, since it is larger than the sum of its proper divisors (440001373341).

1320004120011 is an equidigital number, since it uses as much as digits as its factorization.

1320004120011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 440001373340.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 1320004120011 its reverse (1100214000231), we get a palindrome (2420218120242).

The spelling of 1320004120011 in words is "one trillion, three hundred twenty billion, four million, one hundred twenty thousand, eleven".

Divisors: 1 3 440001373337 1320004120011