Base | Representation |
---|---|
bin | 11110000000110111110011… |
… | …111011101011000101101100 |
3 | 122022101012111010012202022122 |
4 | 132000313303323223011230 |
5 | 114300202202014230234 |
6 | 1144424323110532112 |
7 | 36542531552433320 |
oct | 3600676373530554 |
9 | 568335433182278 |
10 | 132001322414444 |
11 | 390724a026560a |
12 | 1297a8a7967038 |
13 | 5886895aa18c2 |
14 | 2484c80525980 |
15 | 103d9cd6e292e |
hex | 780df3eeb16c |
132001322414444 has 12 divisors (see below), whose sum is σ = 264002644828944. Its totient is φ = 56571995320464.
The previous prime is 132001322414431. The next prime is 132001322414473. The reversal of 132001322414444 is 444414223100231.
132001322414444 is an admirable number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2357166471659 + ... + 2357166471714.
It is an arithmetic number, because the mean of its divisors is an integer number (22000220402412).
Almost surely, 2132001322414444 is an apocalyptic number.
132001322414444 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
132001322414444 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132001322414444 is a wasteful number, since it uses less digits than its factorization.
132001322414444 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4714332943384 (or 4714332943382 counting only the distinct ones).
The product of its (nonzero) digits is 73728, while the sum is 35.
Adding to 132001322414444 its reverse (444414223100231), we get a palindrome (576415545514675).
The spelling of 132001322414444 in words is "one hundred thirty-two trillion, one billion, three hundred twenty-two million, four hundred fourteen thousand, four hundred forty-four".
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