Base | Representation |
---|---|
bin | 111101011101111101… |
… | …1110101100011100011 |
3 | 110121201110010121212110 |
4 | 1322323323311203203 |
5 | 4130320010403011 |
6 | 140350233530403 |
7 | 12352063601466 |
oct | 1727373654343 |
9 | 417643117773 |
10 | 132002044131 |
11 | 50a88792561 |
12 | 216bb273a03 |
13 | c5a88b6429 |
14 | 65633372dd |
15 | 36789cbba6 |
hex | 1ebbef58e3 |
132002044131 has 8 divisors (see below), whose sum is σ = 176004874944. Its totient is φ = 88000288040.
The previous prime is 132002044127. The next prime is 132002044201. The reversal of 132002044131 is 131440200231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 132002044131 - 22 = 132002044127 is a prime.
It is a super-2 number, since 2×1320020441312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 132002044098 and 132002044107.
It is not an unprimeable number, because it can be changed into a prime (132002044331) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 84076 + ... + 520646.
It is an arithmetic number, because the mean of its divisors is an integer number (22000609368).
Almost surely, 2132002044131 is an apocalyptic number.
132002044131 is a deficient number, since it is larger than the sum of its proper divisors (44002830813).
132002044131 is a wasteful number, since it uses less digits than its factorization.
132002044131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 537361.
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 132002044131 its reverse (131440200231), we get a palindrome (263442244362).
The spelling of 132002044131 in words is "one hundred thirty-two billion, two million, forty-four thousand, one hundred thirty-one".
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