Base | Representation |
---|---|
bin | 1100000000010110100110… |
… | …1101111010100010010011 |
3 | 1201201221001012110001101121 |
4 | 3000011221231322202103 |
5 | 3212233011241111111 |
6 | 44024031503543111 |
7 | 2531453314633642 |
oct | 300055155724223 |
9 | 51657035401347 |
10 | 13200208144531 |
11 | 422a1a4406a71 |
12 | 1592356bbaa97 |
13 | 749a0b153a25 |
14 | 338c71a09359 |
15 | 17d57b023871 |
hex | c0169b7a893 |
13200208144531 has 2 divisors, whose sum is σ = 13200208144532. Its totient is φ = 13200208144530.
The previous prime is 13200208144517. The next prime is 13200208144549. The reversal of 13200208144531 is 13544180200231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13200208144531 - 235 = 13165848406163 is a prime.
It is a super-2 number, since 2×132002081445312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13200208147531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600104072265 + 6600104072266.
It is an arithmetic number, because the mean of its divisors is an integer number (6600104072266).
Almost surely, 213200208144531 is an apocalyptic number.
13200208144531 is a deficient number, since it is larger than the sum of its proper divisors (1).
13200208144531 is an equidigital number, since it uses as much as digits as its factorization.
13200208144531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23040, while the sum is 34.
Adding to 13200208144531 its reverse (13544180200231), we get a palindrome (26744388344762).
The spelling of 13200208144531 in words is "thirteen trillion, two hundred billion, two hundred eight million, one hundred forty-four thousand, five hundred thirty-one".
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