Base | Representation |
---|---|
bin | 11110000000111000101000… |
… | …111110011001001011110011 |
3 | 122022101021210010201122020012 |
4 | 132000320220332121023303 |
5 | 114300211012323214422 |
6 | 1144424551300405135 |
7 | 36542562606500162 |
oct | 3600705076311363 |
9 | 568337703648205 |
10 | 132002212319987 |
11 | 39072907622839 |
12 | 1297aab59a67ab |
13 | 58869a8272729 |
14 | 2484d267b53d9 |
15 | 103da318c84e2 |
hex | 780e28f992f3 |
132002212319987 has 2 divisors, whose sum is σ = 132002212319988. Its totient is φ = 132002212319986.
The previous prime is 132002212319951. The next prime is 132002212320119. The reversal of 132002212319987 is 789913212200231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132002212319987 - 224 = 132002195542771 is a prime.
It is not a weakly prime, because it can be changed into another prime (132002212309987) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66001106159993 + 66001106159994.
It is an arithmetic number, because the mean of its divisors is an integer number (66001106159994).
Almost surely, 2132002212319987 is an apocalyptic number.
132002212319987 is a deficient number, since it is larger than the sum of its proper divisors (1).
132002212319987 is an equidigital number, since it uses as much as digits as its factorization.
132002212319987 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 653184, while the sum is 50.
The spelling of 132002212319987 in words is "one hundred thirty-two trillion, two billion, two hundred twelve million, three hundred nineteen thousand, nine hundred eighty-seven".
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