Base | Representation |
---|---|
bin | 1100000000010110101100… |
… | …1101100010000101111001 |
3 | 1201201221002221121112001221 |
4 | 3000011223031202011321 |
5 | 3212233034200211413 |
6 | 44024034201112041 |
7 | 2531454040661536 |
oct | 300055315420571 |
9 | 51657087545057 |
10 | 13200233210233 |
11 | 422a207577223 |
12 | 1592363488621 |
13 | 749a133bbac4 |
14 | 338c75091d8d |
15 | 17d57d32568d |
hex | c016b362179 |
13200233210233 has 4 divisors (see below), whose sum is σ = 13214261089188. Its totient is φ = 13186205331280.
The previous prime is 13200233210231. The next prime is 13200233210257. The reversal of 13200233210233 is 33201233200231.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 2895959869504 + 10304273340729 = 1701752^2 + 3210027^2 .
It is a cyclic number.
It is not a de Polignac number, because 13200233210233 - 21 = 13200233210231 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13200233210198 and 13200233210207.
It is not an unprimeable number, because it can be changed into a prime (13200233210231) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7013938066 + ... + 7013939947.
It is an arithmetic number, because the mean of its divisors is an integer number (3303565272297).
Almost surely, 213200233210233 is an apocalyptic number.
It is an amenable number.
13200233210233 is a deficient number, since it is larger than the sum of its proper divisors (14027878955).
13200233210233 is an equidigital number, since it uses as much as digits as its factorization.
13200233210233 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14027878954.
The product of its (nonzero) digits is 3888, while the sum is 25.
Adding to 13200233210233 its reverse (33201233200231), we get a palindrome (46401466410464).
The spelling of 13200233210233 in words is "thirteen trillion, two hundred billion, two hundred thirty-three million, two hundred ten thousand, two hundred thirty-three".
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