Base | Representation |
---|---|
bin | 10011001101010111111… |
… | …011111110100001010001 |
3 | 11200012020011220010121001 |
4 | 103031113323332201101 |
5 | 133111410224101431 |
6 | 2450225154302001 |
7 | 164240403264232 |
oct | 23152773764121 |
9 | 4605204803531 |
10 | 1320030300241 |
11 | 469904767234 |
12 | 1939b7587901 |
13 | 9762ab508c3 |
14 | 47c658bb089 |
15 | 2450c678e61 |
hex | 13357efe851 |
1320030300241 has 2 divisors, whose sum is σ = 1320030300242. Its totient is φ = 1320030300240.
The previous prime is 1320030300217. The next prime is 1320030300289. The reversal of 1320030300241 is 1420030300231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1070250251841 + 249780048400 = 1034529^2 + 499780^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1320030300241 is a prime.
It is not a weakly prime, because it can be changed into another prime (1320030600241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660015150120 + 660015150121.
It is an arithmetic number, because the mean of its divisors is an integer number (660015150121).
Almost surely, 21320030300241 is an apocalyptic number.
It is an amenable number.
1320030300241 is a deficient number, since it is larger than the sum of its proper divisors (1).
1320030300241 is an equidigital number, since it uses as much as digits as its factorization.
1320030300241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 1320030300241 its reverse (1420030300231), we get a palindrome (2740060600472).
The spelling of 1320030300241 in words is "one trillion, three hundred twenty billion, thirty million, three hundred thousand, two hundred forty-one".
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