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13200311023531 is a prime number
BaseRepresentation
bin1100000000010110111111…
…0110010111011110101011
31201201221022101000211211221
43000011233312113132223
53212233214110223111
644024050021002511
72531456004246502
oct300055766273653
951657271024757
1013200311023531
11422a247494535
121592385553437
13749a26564a88
14338c81549839
1517d585096371
hexc016fd977ab

13200311023531 has 2 divisors, whose sum is σ = 13200311023532. Its totient is φ = 13200311023530.

The previous prime is 13200311023507. The next prime is 13200311023553. The reversal of 13200311023531 is 13532011300231.

It is a strong prime.

It is an emirp because it is prime and its reverse (13532011300231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13200311023531 - 221 = 13200308926379 is a prime.

It is a super-2 number, since 2×132003110235312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13200311023496 and 13200311023505.

It is not a weakly prime, because it can be changed into another prime (13200311063531) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600155511765 + 6600155511766.

It is an arithmetic number, because the mean of its divisors is an integer number (6600155511766).

Almost surely, 213200311023531 is an apocalyptic number.

13200311023531 is a deficient number, since it is larger than the sum of its proper divisors (1).

13200311023531 is an equidigital number, since it uses as much as digits as its factorization.

13200311023531 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1620, while the sum is 25.

Adding to 13200311023531 its reverse (13532011300231), we get a palindrome (26732322323762).

The spelling of 13200311023531 in words is "thirteen trillion, two hundred billion, three hundred eleven million, twenty-three thousand, five hundred thirty-one".