Base | Representation |
---|---|
bin | 1100000000010111000100… |
… | …1011010111000101011011 |
3 | 1201201221100220221211010020 |
4 | 3000011301023113011123 |
5 | 3212233240311213110 |
6 | 44024052134321523 |
7 | 2531456364524544 |
oct | 300056113270533 |
9 | 51657326854106 |
10 | 13200333304155 |
11 | 422a259022278 |
12 | 1592390ab92a3 |
13 | 749a2b06628a |
14 | 338c844a94cb |
15 | 17d586ee7d70 |
hex | c01712d715b |
13200333304155 has 32 divisors (see below), whose sum is σ = 21238745149440. Its totient is φ = 7000779392640.
The previous prime is 13200333304141. The next prime is 13200333304157. The reversal of 13200333304155 is 55140333300231.
It is not a de Polignac number, because 13200333304155 - 215 = 13200333271387 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13200333304157) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 39317086 + ... + 39651404.
It is an arithmetic number, because the mean of its divisors is an integer number (663710785920).
Almost surely, 213200333304155 is an apocalyptic number.
13200333304155 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13200333304155 is a deficient number, since it is larger than the sum of its proper divisors (8038411845285).
13200333304155 is a wasteful number, since it uses less digits than its factorization.
13200333304155 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 349051.
The product of its (nonzero) digits is 48600, while the sum is 33.
Adding to 13200333304155 its reverse (55140333300231), we get a palindrome (68340666604386).
The spelling of 13200333304155 in words is "thirteen trillion, two hundred billion, three hundred thirty-three million, three hundred four thousand, one hundred fifty-five".
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