Base | Representation |
---|---|
bin | 1100000000010111001000… |
… | …0101010010010001001011 |
3 | 1201201221101222112021111201 |
4 | 3000011302011102101023 |
5 | 3212233303203120104 |
6 | 44024053440005031 |
7 | 2531456640556564 |
oct | 300056205222113 |
9 | 51657358467451 |
10 | 13200348488779 |
11 | 422a266653751 |
12 | 1592396000777 |
13 | 749a3125196a |
14 | 338c864dd16b |
15 | 17d5884e70a4 |
hex | c017215244b |
13200348488779 has 2 divisors, whose sum is σ = 13200348488780. Its totient is φ = 13200348488778.
The previous prime is 13200348488773. The next prime is 13200348488857. The reversal of 13200348488779 is 97788484300231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13200348488779 - 27 = 13200348488651 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13200348488779.
It is not a weakly prime, because it can be changed into another prime (13200348488773) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6600174244389 + 6600174244390.
It is an arithmetic number, because the mean of its divisors is an integer number (6600174244390).
Almost surely, 213200348488779 is an apocalyptic number.
13200348488779 is a deficient number, since it is larger than the sum of its proper divisors (1).
13200348488779 is an equidigital number, since it uses as much as digits as its factorization.
13200348488779 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 65028096, while the sum is 64.
The spelling of 13200348488779 in words is "thirteen trillion, two hundred billion, three hundred forty-eight million, four hundred eighty-eight thousand, seven hundred seventy-nine".
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